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Lógica matemática/ avbvd

Expresión avbvd

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    Solución

    Ha introducido [src] 
    a∨b∨d
    $$a \vee b \vee d$$
    Simplificación [src]
    $$a \vee b \vee d$$ 
    a∨b∨d
    Tabla de verdad 
    +---+---+---+--------+
| a | b | d | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNDP [src]
    $$a \vee b \vee d$$ 
    a∨b∨d
    FNCD [src]
    $$a \vee b \vee d$$ 
    a∨b∨d
    FND [src]
    Ya está reducido a FND
    $$a \vee b \vee d$$ 
    a∨b∨d
    FNC [src]
    Ya está reducido a FNC
    $$a \vee b \vee d$$ 
    a∨b∨d
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