Sr Examen
Expresión (!a&b&c)v(!a&(!bv!c))va
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Solución
Ha introducido
[src]
a∨(b∧c∧(¬a))∨((¬a)∧((¬b)∨(¬c)))
$$a \vee \left(\neg a \wedge \left(\neg b \vee \neg c\right)\right) \vee \left(b \wedge c \wedge \neg a\right)$$
Solución detallada
$$a \vee \left(\neg a \wedge \left(\neg b \vee \neg c\right)\right) \vee \left(b \wedge c \wedge \neg a\right) = 1$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+