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Expresión ¬((¬((A∨B)∧C))∨¬(¬((a∧b)∨(b∧C))))

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ¬((¬(c∧(a∨b)))∨(¬(¬((a∧b)∨(b∧c)))))
    $$\neg \left(\neg \left(c \wedge \left(a \vee b\right)\right) \vee \neg \left(\neg \left(\left(a \wedge b\right) \vee \left(b \wedge c\right)\right)\right)\right)$$
    Solución detallada
    $$\neg \left(c \wedge \left(a \vee b\right)\right) = \left(\neg a \wedge \neg b\right) \vee \neg c$$
    $$\left(a \wedge b\right) \vee \left(b \wedge c\right) = b \wedge \left(a \vee c\right)$$
    $$\neg \left(\left(a \wedge b\right) \vee \left(b \wedge c\right)\right) = \left(\neg a \wedge \neg c\right) \vee \neg b$$
    $$\neg \left(\neg \left(\left(a \wedge b\right) \vee \left(b \wedge c\right)\right)\right) = b \wedge \left(a \vee c\right)$$
    $$\neg \left(c \wedge \left(a \vee b\right)\right) \vee \neg \left(\neg \left(\left(a \wedge b\right) \vee \left(b \wedge c\right)\right)\right) = b \vee \neg a \vee \neg c$$
    $$\neg \left(\neg \left(c \wedge \left(a \vee b\right)\right) \vee \neg \left(\neg \left(\left(a \wedge b\right) \vee \left(b \wedge c\right)\right)\right)\right) = a \wedge c \wedge \neg b$$
    Simplificación [src]
    $$a \wedge c \wedge \neg b$$
    a∧c∧(¬b)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNDP [src]
    $$a \wedge c \wedge \neg b$$
    a∧c∧(¬b)
    FNCD [src]
    $$a \wedge c \wedge \neg b$$
    a∧c∧(¬b)
    FND [src]
    Ya está reducido a FND
    $$a \wedge c \wedge \neg b$$
    a∧c∧(¬b)
    FNC [src]
    Ya está reducido a FNC
    $$a \wedge c \wedge \neg b$$
    a∧c∧(¬b)