Expresión ¬((¬((A∨B)∧C))∨¬(¬((a∧b)∨(b∧C))))
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
¬(c∧(a∨b))=(¬a∧¬b)∨¬c(a∧b)∨(b∧c)=b∧(a∨c)¬((a∧b)∨(b∧c))=(¬a∧¬c)∨¬b¬(¬((a∧b)∨(b∧c)))=b∧(a∨c)¬(c∧(a∨b))∨¬(¬((a∧b)∨(b∧c)))=b∨¬a∨¬c¬(¬(c∧(a∨b))∨¬(¬((a∧b)∨(b∧c))))=a∧c∧¬b
a∧c∧¬b
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
a∧c∧¬b
a∧c∧¬b
Ya está reducido a FND
a∧c∧¬b
Ya está reducido a FNC
a∧c∧¬b