Sr Examen

Expresión ((x¬yv¬xz)v(y¬zv¬xy))((xyv¬x¬z)v(xzv¬y))

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ((¬y)∨(x∧y)∨(x∧z)∨((¬x)∧(¬z)))∧((x∧(¬y))∨(y∧(¬x))∨(y∧(¬z))∨(z∧(¬x)))
    $$\left(\left(x \wedge \neg y\right) \vee \left(y \wedge \neg x\right) \vee \left(y \wedge \neg z\right) \vee \left(z \wedge \neg x\right)\right) \wedge \left(\left(x \wedge y\right) \vee \left(x \wedge z\right) \vee \left(\neg x \wedge \neg z\right) \vee \neg y\right)$$
    Solución detallada
    $$\left(x \wedge y\right) \vee \left(x \wedge z\right) \vee \left(\neg x \wedge \neg z\right) \vee \neg y = x \vee \neg y \vee \neg z$$
    $$\left(x \wedge \neg y\right) \vee \left(y \wedge \neg x\right) \vee \left(y \wedge \neg z\right) \vee \left(z \wedge \neg x\right) = \left(x \wedge \neg y\right) \vee \left(x \wedge \neg z\right) \vee \left(y \wedge \neg x\right) \vee \left(y \wedge \neg z\right) \vee \left(z \wedge \neg x\right) \vee \left(z \wedge \neg y\right)$$
    $$\left(\left(x \wedge \neg y\right) \vee \left(y \wedge \neg x\right) \vee \left(y \wedge \neg z\right) \vee \left(z \wedge \neg x\right)\right) \wedge \left(\left(x \wedge y\right) \vee \left(x \wedge z\right) \vee \left(\neg x \wedge \neg z\right) \vee \neg y\right) = \left(x \wedge \neg z\right) \vee \left(y \wedge \neg z\right) \vee \left(z \wedge \neg y\right)$$
    Simplificación [src]
    $$\left(x \wedge \neg z\right) \vee \left(y \wedge \neg z\right) \vee \left(z \wedge \neg y\right)$$
    (x∧(¬z))∨(y∧(¬z))∨(z∧(¬y))
    Tabla de verdad
    +---+---+---+--------+
    | x | y | z | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$\left(x \wedge \neg z\right) \vee \left(y \wedge \neg z\right) \vee \left(z \wedge \neg y\right)$$
    (x∧(¬z))∨(y∧(¬z))∨(z∧(¬y))
    FNC [src]
    $$\left(z \vee \neg z\right) \wedge \left(\neg y \vee \neg z\right) \wedge \left(x \vee y \vee z\right) \wedge \left(x \vee y \vee \neg y\right) \wedge \left(x \vee z \vee \neg z\right) \wedge \left(x \vee \neg y \vee \neg z\right) \wedge \left(y \vee z \vee \neg z\right) \wedge \left(y \vee \neg y \vee \neg z\right)$$
    (z∨(¬z))∧(x∨y∨z)∧((¬y)∨(¬z))∧(x∨y∨(¬y))∧(x∨z∨(¬z))∧(y∨z∨(¬z))∧(x∨(¬y)∨(¬z))∧(y∨(¬y)∨(¬z))
    FNCD [src]
    $$\left(\neg y \vee \neg z\right) \wedge \left(x \vee y \vee z\right)$$
    (x∨y∨z)∧((¬y)∨(¬z))
    FNDP [src]
    $$\left(x \wedge \neg z\right) \vee \left(y \wedge \neg z\right) \vee \left(z \wedge \neg y\right)$$
    (x∧(¬z))∨(y∧(¬z))∨(z∧(¬y))