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Lógica matemática/ notaandbcdornotaandnotcandd

Expresión notaandbcdornotaandnotcandd

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    Solución

    Ha introducido [src] 
    (d∧(¬a)∧(¬c))∨(b∧c∧d∧(¬a))
    $$\left(d \wedge \neg a \wedge \neg c\right) \vee \left(b \wedge c \wedge d \wedge \neg a\right)$$
    Solución detallada
    $$\left(d \wedge \neg a \wedge \neg c\right) \vee \left(b \wedge c \wedge d \wedge \neg a\right) = d \wedge \neg a \wedge \left(b \vee \neg c\right)$$
    Simplificación [src]
    $$d \wedge \neg a \wedge \left(b \vee \neg c\right)$$ 
    d∧(¬a)∧(b∨(¬c))
    Tabla de verdad 
    +---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 0      |
+---+---+---+---+--------+
    FND [src]
    $$\left(b \wedge d \wedge \neg a\right) \vee \left(d \wedge \neg a \wedge \neg c\right)$$ 
    (b∧d∧(¬a))∨(d∧(¬a)∧(¬c))
    FNC [src]
    Ya está reducido a FNC
    $$d \wedge \neg a \wedge \left(b \vee \neg c\right)$$ 
    d∧(¬a)∧(b∨(¬c))
    FNDP [src]
    $$\left(b \wedge d \wedge \neg a\right) \vee \left(d \wedge \neg a \wedge \neg c\right)$$ 
    (b∧d∧(¬a))∨(d∧(¬a)∧(¬c))
    FNCD [src]
    $$d \wedge \neg a \wedge \left(b \vee \neg c\right)$$ 
    d∧(¬a)∧(b∨(¬c))
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