Expresión не((неx^неy)->(xv(z^неt)))
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(¬x∧¬y)⇒(x∨(z∧¬t))=x∨y∨(z∧¬t)(¬x∧¬y)⇒(x∨(z∧¬t))=¬x∧¬y∧(t∨¬z)
¬x∧¬y∧(t∨¬z)
Tabla de verdad
+---+---+---+---+--------+
| t | x | y | z | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 0 |
+---+---+---+---+--------+
(t∧¬x∧¬y)∨(¬x∧¬y∧¬z)
(t∧(¬x)∧(¬y))∨((¬x)∧(¬y)∧(¬z))
(t∧¬x∧¬y)∨(¬x∧¬y∧¬z)
(t∧(¬x)∧(¬y))∨((¬x)∧(¬y)∧(¬z))
¬x∧¬y∧(t∨¬z)
Ya está reducido a FNC
¬x∧¬y∧(t∨¬z)