Expresión avbvcvb(a^bvc^avbvc)va^b
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Solución
Solución detallada
b∨c∨(a∧b)∨(a∧c)=b∨cb∧(b∨c∨(a∧b)∨(a∧c))=ba∨b∨c∨(a∧b)∨(b∧(b∨c∨(a∧b)∨(a∧c)))=a∨b∨c
a∨b∨c
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
a∨b∨c
Ya está reducido a FND
a∨b∨c
Ya está reducido a FNC
a∨b∨c
a∨b∨c