Sr Examen
Expresión (C⇒A)⇒(¬B∧C)⇒A
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Solución
Ha introducido
[src]
((c⇒a)⇒(c∧(¬b)))⇒a
$$\left(\left(c \Rightarrow a\right) \Rightarrow \left(c \wedge \neg b\right)\right) \Rightarrow a$$
Solución detallada
$$c \Rightarrow a = a \vee \neg c$$
$$\left(c \Rightarrow a\right) \Rightarrow \left(c \wedge \neg b\right) = c \wedge \left(\neg a \vee \neg b\right)$$
$$\left(\left(c \Rightarrow a\right) \Rightarrow \left(c \wedge \neg b\right)\right) \Rightarrow a = a \vee \neg c$$
$$\left(c \Rightarrow a\right) \Rightarrow \left(c \wedge \neg b\right) = c \wedge \left(\neg a \vee \neg b\right)$$
$$\left(\left(c \Rightarrow a\right) \Rightarrow \left(c \wedge \neg b\right)\right) \Rightarrow a = a \vee \neg c$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+