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Expresión avdv¬a∧b∧cv¬a∧¬b∧c∨a∧b∧c

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    a∨d∨(a∧b∧c)∨(b∧c∧(¬a))∨(c∧(¬a)∧(¬b))
    $$a \vee d \vee \left(a \wedge b \wedge c\right) \vee \left(b \wedge c \wedge \neg a\right) \vee \left(c \wedge \neg a \wedge \neg b\right)$$
    Solución detallada
    $$a \vee d \vee \left(a \wedge b \wedge c\right) \vee \left(b \wedge c \wedge \neg a\right) \vee \left(c \wedge \neg a \wedge \neg b\right) = a \vee c \vee d$$
    Simplificación [src]
    $$a \vee c \vee d$$
    a∨c∨d
    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | d | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$a \vee c \vee d$$
    a∨c∨d
    FND [src]
    Ya está reducido a FND
    $$a \vee c \vee d$$
    a∨c∨d
    FNDP [src]
    $$a \vee c \vee d$$
    a∨c∨d
    FNCD [src]
    $$a \vee c \vee d$$
    a∨c∨d