Sr Examen
Expresión ¬C&(¬AvB)vA&B&C
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(a∧b∧c)∨((¬c)∧(b∨(¬a)))
$$\left(\neg c \wedge \left(b \vee \neg a\right)\right) \vee \left(a \wedge b \wedge c\right)$$
Solución detallada
$$\left(\neg c \wedge \left(b \vee \neg a\right)\right) \vee \left(a \wedge b \wedge c\right) = \left(a \wedge b\right) \vee \left(\neg a \wedge \neg c\right)$$
Simplificación
[src]
$$\left(a \wedge b\right) \vee \left(\neg a \wedge \neg c\right)$$
(a∧b)∨((¬a)∧(¬c))
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+
FND
[src]
Ya está reducido a FND
$$\left(a \wedge b\right) \vee \left(\neg a \wedge \neg c\right)$$
(a∧b)∨((¬a)∧(¬c))
FNC
[src]
$$\left(a \vee \neg a\right) \wedge \left(a \vee \neg c\right) \wedge \left(b \vee \neg a\right) \wedge \left(b \vee \neg c\right)$$
(a∨(¬a))∧(a∨(¬c))∧(b∨(¬a))∧(b∨(¬c))