Expresión a&!b&!cv!(b&c)&!(a&d)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\neg \left(a \wedge d\right) = \neg a \vee \neg d$$
$$\neg \left(b \wedge c\right) = \neg b \vee \neg c$$
$$\neg \left(a \wedge d\right) \wedge \neg \left(b \wedge c\right) = \left(\neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg c\right) \vee \left(\neg b \wedge \neg d\right) \vee \left(\neg c \wedge \neg d\right)$$
$$\left(\neg \left(a \wedge d\right) \wedge \neg \left(b \wedge c\right)\right) \vee \left(a \wedge \neg b \wedge \neg c\right) = \left(\neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg c\right) \vee \left(\neg b \wedge \neg c\right) \vee \left(\neg b \wedge \neg d\right) \vee \left(\neg c \wedge \neg d\right)$$
$$\left(\neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg c\right) \vee \left(\neg b \wedge \neg c\right) \vee \left(\neg b \wedge \neg d\right) \vee \left(\neg c \wedge \neg d\right)$$
((¬a)∧(¬b))∨((¬a)∧(¬c))∨((¬b)∧(¬c))∨((¬b)∧(¬d))∨((¬c)∧(¬d))
Tabla de verdad
+---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 0 |
+---+---+---+---+--------+
$$\left(\neg b \vee \neg c\right) \wedge \left(\neg a \vee \neg b \vee \neg c\right) \wedge \left(\neg a \vee \neg b \vee \neg d\right) \wedge \left(\neg a \vee \neg c \vee \neg d\right) \wedge \left(\neg b \vee \neg c \vee \neg d\right) \wedge \left(\neg a \vee \neg b \vee \neg c \vee \neg d\right)$$
((¬b)∨(¬c))∧((¬a)∨(¬b)∨(¬c))∧((¬a)∨(¬b)∨(¬d))∧((¬a)∨(¬c)∨(¬d))∧((¬b)∨(¬c)∨(¬d))∧((¬a)∨(¬b)∨(¬c)∨(¬d))
$$\left(\neg b \vee \neg c\right) \wedge \left(\neg a \vee \neg b \vee \neg d\right) \wedge \left(\neg a \vee \neg c \vee \neg d\right)$$
((¬b)∨(¬c))∧((¬a)∨(¬b)∨(¬d))∧((¬a)∨(¬c)∨(¬d))
Ya está reducido a FND
$$\left(\neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg c\right) \vee \left(\neg b \wedge \neg c\right) \vee \left(\neg b \wedge \neg d\right) \vee \left(\neg c \wedge \neg d\right)$$
((¬a)∧(¬b))∨((¬a)∧(¬c))∨((¬b)∧(¬c))∨((¬b)∧(¬d))∨((¬c)∧(¬d))
$$\left(\neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg c\right) \vee \left(\neg b \wedge \neg c\right) \vee \left(\neg b \wedge \neg d\right) \vee \left(\neg c \wedge \neg d\right)$$
((¬a)∧(¬b))∨((¬a)∧(¬c))∨((¬b)∧(¬c))∨((¬b)∧(¬d))∨((¬c)∧(¬d))