Sr Examen
Expresión ava&b&b&(d=>c)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
a∨(a∧b∧(d⇒c))
$$a \vee \left(a \wedge b \wedge \left(d \Rightarrow c\right)\right)$$
Solución detallada
$$d \Rightarrow c = c \vee \neg d$$
$$a \wedge b \wedge \left(d \Rightarrow c\right) = a \wedge b \wedge \left(c \vee \neg d\right)$$
$$a \vee \left(a \wedge b \wedge \left(d \Rightarrow c\right)\right) = a$$
$$a \wedge b \wedge \left(d \Rightarrow c\right) = a \wedge b \wedge \left(c \vee \neg d\right)$$
$$a \vee \left(a \wedge b \wedge \left(d \Rightarrow c\right)\right) = a$$
Tabla de verdad
+---+---+---+---+--------+ | a | b | c | d | result | +===+===+===+===+========+ | 0 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 0 | 0 | 1 | 0 | +---+---+---+---+--------+ | 0 | 0 | 1 | 0 | 0 | +---+---+---+---+--------+ | 0 | 0 | 1 | 1 | 0 | +---+---+---+---+--------+ | 0 | 1 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 0 | 1 | 0 | +---+---+---+---+--------+ | 0 | 1 | 1 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 1 | 1 | 0 | +---+---+---+---+--------+ | 1 | 0 | 0 | 0 | 1 | +---+---+---+---+--------+ | 1 | 0 | 0 | 1 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 0 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 1 | 1 | 1 | 1 | +---+---+---+---+--------+