Sr Examen
Lógica matemática/ cva&c+¬a&b&c

Expresión cva&c+¬a&b&c

El profesor se sorprenderá mucho al ver tu solución correcta😉

⌨

    Solución

    Ha introducido [src] 
    c∨(a∧c)∨(b∧c∧(¬a))
    $$c \vee \left(a \wedge c\right) \vee \left(b \wedge c \wedge \neg a\right)$$
    Solución detallada
    $$c \vee \left(a \wedge c\right) \vee \left(b \wedge c \wedge \neg a\right) = c$$
    Simplificación [src]
    $$c$$ 
    c
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNCD [src]
    $$c$$ 
    c
    FNC [src]
    Ya está reducido a FNC
    $$c$$ 
    c
    FNDP [src]
    $$c$$ 
    c
    FND [src]
    Ya está reducido a FND
    $$c$$ 
    c
    © Sr Examen