Expresión ¬(x2∨x1)∨¬(x3¬x1)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\neg \left(x_{1} \vee x_{2}\right) = \neg x_{1} \wedge \neg x_{2}$$
$$\neg \left(x_{3} \wedge \neg x_{1}\right) = x_{1} \vee \neg x_{3}$$
$$\neg \left(x_{3} \wedge \neg x_{1}\right) \vee \neg \left(x_{1} \vee x_{2}\right) = x_{1} \vee \neg x_{2} \vee \neg x_{3}$$
$$x_{1} \vee \neg x_{2} \vee \neg x_{3}$$
Tabla de verdad
+----+----+----+--------+
| x1 | x2 | x3 | result |
+====+====+====+========+
| 0 | 0 | 0 | 1 |
+----+----+----+--------+
| 0 | 0 | 1 | 1 |
+----+----+----+--------+
| 0 | 1 | 0 | 1 |
+----+----+----+--------+
| 0 | 1 | 1 | 0 |
+----+----+----+--------+
| 1 | 0 | 0 | 1 |
+----+----+----+--------+
| 1 | 0 | 1 | 1 |
+----+----+----+--------+
| 1 | 1 | 0 | 1 |
+----+----+----+--------+
| 1 | 1 | 1 | 1 |
+----+----+----+--------+
Ya está reducido a FNC
$$x_{1} \vee \neg x_{2} \vee \neg x_{3}$$
Ya está reducido a FND
$$x_{1} \vee \neg x_{2} \vee \neg x_{3}$$
$$x_{1} \vee \neg x_{2} \vee \neg x_{3}$$
$$x_{1} \vee \neg x_{2} \vee \neg x_{3}$$