Sr Examen
Lógica matemática/ avbvcv¬d=0

Expresión avbvcv¬d=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    ¬(a∨b∨c∨(¬d))
    $$\neg \left(a \vee b \vee c \vee \neg d\right)$$
    Solución detallada
    $$\neg \left(a \vee b \vee c \vee \neg d\right) = d \wedge \neg a \wedge \neg b \wedge \neg c$$
    Simplificación [src]
    $$d \wedge \neg a \wedge \neg b \wedge \neg c$$ 
    d∧(¬a)∧(¬b)∧(¬c)
    Tabla de verdad 
    +---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 0      |
+---+---+---+---+--------+
    FNDP [src]
    $$d \wedge \neg a \wedge \neg b \wedge \neg c$$ 
    d∧(¬a)∧(¬b)∧(¬c)
    FND [src]
    Ya está reducido a FND
    $$d \wedge \neg a \wedge \neg b \wedge \neg c$$ 
    d∧(¬a)∧(¬b)∧(¬c)
    FNCD [src]
    $$d \wedge \neg a \wedge \neg b \wedge \neg c$$ 
    d∧(¬a)∧(¬b)∧(¬c)
    FNC [src]
    Ya está reducido a FNC
    $$d \wedge \neg a \wedge \neg b \wedge \neg c$$ 
    d∧(¬a)∧(¬b)∧(¬c)
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