Sr Examen
Lógica matemática/ Pv(~P&~Q&R)

Expresión Pv(~P&~Q&R)

El profesor se sorprenderá mucho al ver tu solución correcta😉

⌨

    Solución

    Ha introducido [src] 
    p∨(r∧(¬p)∧(¬q))
    $$p \vee \left(r \wedge \neg p \wedge \neg q\right)$$
    Solución detallada
    $$p \vee \left(r \wedge \neg p \wedge \neg q\right) = p \vee \left(r \wedge \neg q\right)$$
    Simplificación [src]
    $$p \vee \left(r \wedge \neg q\right)$$ 
    p∨(r∧(¬q))
    Tabla de verdad 
    +---+---+---+--------+
| p | q | r | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 0      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$p \vee \left(r \wedge \neg q\right)$$ 
    p∨(r∧(¬q))
    FNDP [src]
    $$p \vee \left(r \wedge \neg q\right)$$ 
    p∨(r∧(¬q))
    FNC [src]
    $$\left(p \vee r\right) \wedge \left(p \vee \neg q\right)$$ 
    (p∨r)∧(p∨(¬q))
    FNCD [src]
    $$\left(p \vee r\right) \wedge \left(p \vee \neg q\right)$$ 
    (p∨r)∧(p∨(¬q))
    © Sr Examen – Калькулятор