Sr Examen

Expresión ¬(A→(B∧C)→D)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ¬((a⇒(b∧c))⇒d)
    (a(bc))⇏d\left(a \Rightarrow \left(b \wedge c\right)\right) \not\Rightarrow d
    Solución detallada
    a(bc)=(bc)¬aa \Rightarrow \left(b \wedge c\right) = \left(b \wedge c\right) \vee \neg a
    (a(bc))d=d(a¬b)(a¬c)\left(a \Rightarrow \left(b \wedge c\right)\right) \Rightarrow d = d \vee \left(a \wedge \neg b\right) \vee \left(a \wedge \neg c\right)
    (a(bc))⇏d=¬d(b¬a)(c¬a)\left(a \Rightarrow \left(b \wedge c\right)\right) \not\Rightarrow d = \neg d \wedge \left(b \vee \neg a\right) \wedge \left(c \vee \neg a\right)
    Simplificación [src]
    ¬d(b¬a)(c¬a)\neg d \wedge \left(b \vee \neg a\right) \wedge \left(c \vee \neg a\right)
    (¬d)∧(b∨(¬a))∧(c∨(¬a))
    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | d | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    ¬d(b¬a)(c¬a)\neg d \wedge \left(b \vee \neg a\right) \wedge \left(c \vee \neg a\right)
    (¬d)∧(b∨(¬a))∧(c∨(¬a))
    FNDP [src]
    (¬a¬d)(bc¬d)\left(\neg a \wedge \neg d\right) \vee \left(b \wedge c \wedge \neg d\right)
    ((¬a)∧(¬d))∨(b∧c∧(¬d))
    FND [src]
    (¬a¬d)(bc¬d)(b¬a¬d)(c¬a¬d)\left(\neg a \wedge \neg d\right) \vee \left(b \wedge c \wedge \neg d\right) \vee \left(b \wedge \neg a \wedge \neg d\right) \vee \left(c \wedge \neg a \wedge \neg d\right)
    ((¬a)∧(¬d))∨(b∧c∧(¬d))∨(b∧(¬a)∧(¬d))∨(c∧(¬a)∧(¬d))
    FNCD [src]
    ¬d(b¬a)(c¬a)\neg d \wedge \left(b \vee \neg a\right) \wedge \left(c \vee \neg a\right)
    (¬d)∧(b∨(¬a))∧(c∨(¬a))