Sr Examen
Expresión ¬A&(¬(P⇒Q))
El profesor se sorprenderá mucho al ver tu solución correcta😉
⌨
Solución
Solución detallada
$$p \Rightarrow q = q \vee \neg p$$
$$p \not\Rightarrow q = p \wedge \neg q$$
$$\neg a \wedge p \not\Rightarrow q = p \wedge \neg a \wedge \neg q$$
$$p \not\Rightarrow q = p \wedge \neg q$$
$$\neg a \wedge p \not\Rightarrow q = p \wedge \neg a \wedge \neg q$$
Tabla de verdad
+---+---+---+--------+ | a | p | q | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+