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(12*x^2)-2*x*y+4*x=0; -x^2-12=0

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Solución

Ha introducido [src]
    2                  
12*x  - 2*x*y + 4*x = 0
4x+(12x22xy)=04 x + \left(12 x^{2} - 2 x y\right) = 0
   2         
- x  - 12 = 0
x212=0- x^{2} - 12 = 0
-x^2 - 12 = 0
Respuesta rápida
x1=23ix_{1} = - 2 \sqrt{3} i
=
23i- 2 \sqrt{3} i
=
-3.46410161513775*i

y1=2123iy_{1} = 2 - 12 \sqrt{3} i
=
2123i2 - 12 \sqrt{3} i
=
2 - 20.7846096908265*i
x2=23ix_{2} = 2 \sqrt{3} i
=
23i2 \sqrt{3} i
=
3.46410161513775*i

y2=2+123iy_{2} = 2 + 12 \sqrt{3} i
=
2+123i2 + 12 \sqrt{3} i
=
2 + 20.7846096908265*i