Sr Examen
ax^2+3ax+4^(1+sqrt(y))=8; x+2*4^y=1
Solución
Ha introducido
[src]
___ 2 1 + \/ y a*x + 3*a*x + 4 = 8
$$4^{\sqrt{y} + 1} + \left(a x^{2} + 3 a x\right) = 8$$
y x + 2*4 = 1
$$2 \cdot 4^{y} + x = 1$$
2*4^y + x = 1
Respuesta rápida
$$x_{1} = 1 - 2^{2 y + 1}$$
=
$$1 - 2^{2 y + 1}$$
=
$$a_{1} = \frac{4 - 2 \cdot 4^{\sqrt{y}}}{2 \cdot 2^{4 y} - 5 \cdot 2^{2 y} + 2}$$
=
$$\frac{4 - 2 \cdot 4^{\sqrt{y}}}{2 \cdot 2^{4 y} - 5 \cdot 2^{2 y} + 2}$$
=
=
$$1 - 2^{2 y + 1}$$
=
1 - 2^(1 + 2*y)
$$a_{1} = \frac{4 - 2 \cdot 4^{\sqrt{y}}}{2 \cdot 2^{4 y} - 5 \cdot 2^{2 y} + 2}$$
=
$$\frac{4 - 2 \cdot 4^{\sqrt{y}}}{2 \cdot 2^{4 y} - 5 \cdot 2^{2 y} + 2}$$
=
(4 - 2*4^(y^0.5))/(2 + 2*2^(4*y) - 5*2^(2*y))