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xy=3; x^2+y^2=8

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Solución

Ha introducido [src]
x*y = 3
$$x y = 3$$
 2    2    
x  + y  = 8
$$x^{2} + y^{2} = 8$$
x^2 + y^2 = 8
Respuesta rápida
$$x_{1} = - \frac{\left(-4 - \sqrt{7}\right) \sqrt{4 - \sqrt{7}}}{3}$$
=
$$\frac{\sqrt{4 - \sqrt{7}} \left(\sqrt{7} + 4\right)}{3}$$
=
2.57793547457352

$$y_{1} = \sqrt{4 - \sqrt{7}}$$
=
$$\sqrt{4 - \sqrt{7}}$$
=
1.16372191220042
$$x_{2} = \frac{\left(-4 - \sqrt{7}\right) \sqrt{4 - \sqrt{7}}}{3}$$
=
$$- \frac{\sqrt{4 - \sqrt{7}} \left(\sqrt{7} + 4\right)}{3}$$
=
-2.57793547457352

$$y_{2} = - \sqrt{4 - \sqrt{7}}$$
=
$$- \sqrt{4 - \sqrt{7}}$$
=
-1.16372191220042
$$x_{3} = - \frac{\left(-4 + \sqrt{7}\right) \sqrt{\sqrt{7} + 4}}{3}$$
=
$$\frac{\left(4 - \sqrt{7}\right) \sqrt{\sqrt{7} + 4}}{3}$$
=
1.16372191220042

$$y_{3} = \sqrt{\sqrt{7} + 4}$$
=
$$\sqrt{\sqrt{7} + 4}$$
=
2.57793547457352
$$x_{4} = \frac{\left(-4 + \sqrt{7}\right) \sqrt{\sqrt{7} + 4}}{3}$$
=
$$\frac{\left(-4 + \sqrt{7}\right) \sqrt{\sqrt{7} + 4}}{3}$$
=
-1.16372191220042

$$y_{4} = - \sqrt{\sqrt{7} + 4}$$
=
$$- \sqrt{\sqrt{7} + 4}$$
=
-2.57793547457352
Respuesta numérica [src]
x1 = 1.163721912200423
y1 = 2.577935474573518
x2 = -2.577935474573518
y2 = -1.163721912200423
x2 = -2.577935474573518
y2 = -1.163721912200423