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Solución de sistemas de ecuaciones/ xy=3; x^2+y^2=8

xy=3; x^2+y^2=8

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Solución

Ha introducido [src] 
x*y = 3
xy=3x y = 3 
 2    2    
x  + y  = 8
x2+y2=8x^{2} + y^{2} = 8 
x^2 + y^2 = 8
Respuesta rápida
x1=−(−4−7)4−73x_{1} = - \frac{\left(-4 - \sqrt{7}\right) \sqrt{4 - \sqrt{7}}}{3}
=
4−7(7+4)3\frac{\sqrt{4 - \sqrt{7}} \left(\sqrt{7} + 4\right)}{3}
=
2.57793547457352

y1=4−7y_{1} = \sqrt{4 - \sqrt{7}}
=
4−7\sqrt{4 - \sqrt{7}}
=
1.16372191220042
x2=(−4−7)4−73x_{2} = \frac{\left(-4 - \sqrt{7}\right) \sqrt{4 - \sqrt{7}}}{3}
=
−4−7(7+4)3- \frac{\sqrt{4 - \sqrt{7}} \left(\sqrt{7} + 4\right)}{3}
=
-2.57793547457352

y2=−4−7y_{2} = - \sqrt{4 - \sqrt{7}}
=
−4−7- \sqrt{4 - \sqrt{7}}
=
-1.16372191220042
x3=−(−4+7)7+43x_{3} = - \frac{\left(-4 + \sqrt{7}\right) \sqrt{\sqrt{7} + 4}}{3}
=
(4−7)7+43\frac{\left(4 - \sqrt{7}\right) \sqrt{\sqrt{7} + 4}}{3}
=
1.16372191220042

y3=7+4y_{3} = \sqrt{\sqrt{7} + 4}
=
7+4\sqrt{\sqrt{7} + 4}
=
2.57793547457352
x4=(−4+7)7+43x_{4} = \frac{\left(-4 + \sqrt{7}\right) \sqrt{\sqrt{7} + 4}}{3}
=
(−4+7)7+43\frac{\left(-4 + \sqrt{7}\right) \sqrt{\sqrt{7} + 4}}{3}
=
-1.16372191220042

y4=−7+4y_{4} = - \sqrt{\sqrt{7} + 4}
=
−7+4- \sqrt{\sqrt{7} + 4}
=
-2.57793547457352
Respuesta numérica [src] 
x1 = 1.163721912200423
y1 = 2.577935474573518
x2 = -2.577935474573518
y2 = -1.163721912200423
x2 = -2.577935474573518
y2 = -1.163721912200423
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