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Solución de sistemas de ecuaciones/ cos(x+y)=0; sinx=-1

cos(x+y)=0; sinx=-1

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Gráfico:

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Solución

Ha introducido [src] 
cos(x + y) = 0
cos⁡(x+y)=0\cos{\left(x + y \right)} = 0 
sin(x) = -1
sin⁡(x)=−1\sin{\left(x \right)} = -1 
sin(x) = -1
Respuesta rápida
x1=−π2x_{1} = - \frac{\pi}{2}
=
−π2- \frac{\pi}{2}
=
-1.57079632679490

y1=0y_{1} = 0
=
00
=
0
x2=−π2x_{2} = - \frac{\pi}{2}
=
−π2- \frac{\pi}{2}
=
-1.57079632679490

y2=πy_{2} = \pi
=
π\pi
=
3.14159265358979
x3=3π2x_{3} = \frac{3 \pi}{2}
=
3π2\frac{3 \pi}{2}
=
4.71238898038469

y3=0y_{3} = 0
=
00
=
0
x4=3π2x_{4} = \frac{3 \pi}{2}
=
3π2\frac{3 \pi}{2}
=
4.71238898038469

y4=πy_{4} = \pi
=
π\pi
=
3.14159265358979
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