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Solución de sistemas de ecuaciones/ siny*cosx=-1/2; sinx*cosy=-1/2

siny*cosx=-1/2; sinx*cosy=-1/2

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Solución

Ha introducido [src] 
sin(y)*cos(x) = -1/2
sin⁡(y)cos⁡(x)=−12\sin{\left(y \right)} \cos{\left(x \right)} = - \frac{1}{2} 
sin(x)*cos(y) = -1/2
sin⁡(x)cos⁡(y)=−12\sin{\left(x \right)} \cos{\left(y \right)} = - \frac{1}{2} 
sin(x)*cos(y) = -1/2
Respuesta rápida
x1=−π4x_{1} = - \frac{\pi}{4}
=
−π4- \frac{\pi}{4}
=
-0.785398163397448

y1=−π4y_{1} = - \frac{\pi}{4}
=
−π4- \frac{\pi}{4}
=
-0.785398163397448
x2=π4x_{2} = \frac{\pi}{4}
=
π4\frac{\pi}{4}
=
0.785398163397448

y2=−3π4y_{2} = - \frac{3 \pi}{4}
=
−3π4- \frac{3 \pi}{4}
=
-2.35619449019234
x3=3π4x_{3} = \frac{3 \pi}{4}
=
3π4\frac{3 \pi}{4}
=
2.35619449019234

y3=3π4y_{3} = \frac{3 \pi}{4}
=
3π4\frac{3 \pi}{4}
=
2.35619449019234
x4=5π4x_{4} = \frac{5 \pi}{4}
=
5π4\frac{5 \pi}{4}
=
3.92699081698724

y4=π4y_{4} = \frac{\pi}{4}
=
π4\frac{\pi}{4}
=
0.785398163397448
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