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xy=4; y=x²

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Solución

Ha introducido [src]
x*y = 4
$$x y = 4$$
     2
y = x 
$$y = x^{2}$$
y = x^2
Respuesta rápida
$$x_{1} = 2^{\frac{2}{3}}$$
=
$$2^{\frac{2}{3}}$$
=
1.58740105196820

$$y_{1} = 2 \sqrt[3]{2}$$
=
$$2 \sqrt[3]{2}$$
=
2.51984209978975
$$x_{2} = \frac{\left(- \sqrt[3]{2} - \sqrt[3]{2} \sqrt{3} i\right)^{2}}{4}$$
=
$$\frac{2^{\frac{2}{3}} \left(-1 + \sqrt{3} i\right)}{2}$$
=
-0.7937005259841 + 1.3747296369986*i

$$y_{2} = - \sqrt[3]{2} - \sqrt[3]{2} \sqrt{3} i$$
=
$$- \sqrt[3]{2} \left(1 + \sqrt{3} i\right)$$
=
-1.25992104989487 - 2.18224727194344*i
$$x_{3} = \frac{\left(- \sqrt[3]{2} + \sqrt[3]{2} \sqrt{3} i\right)^{2}}{4}$$
=
$$\frac{2^{\frac{2}{3}} \left(1 - \sqrt{3} i\right)^{2}}{4}$$
=
-0.7937005259841 - 1.3747296369986*i

$$y_{3} = - \sqrt[3]{2} + \sqrt[3]{2} \sqrt{3} i$$
=
$$\sqrt[3]{2} \left(-1 + \sqrt{3} i\right)$$
=
-1.25992104989487 + 2.18224727194344*i
Respuesta numérica [src]
x1 = 1.587401051968199
y1 = 2.519842099789746
x1 = 1.587401051968199
y1 = 2.519842099789746