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xy=4; y=x²

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Gráfico:

interior superior

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Solución

Ha introducido [src]
x*y = 4
xy=4x y = 4
     2
y = x 
y=x2y = x^{2}
y = x^2
Respuesta rápida
x1=223x_{1} = 2^{\frac{2}{3}}
=
2232^{\frac{2}{3}}
=
1.58740105196820

y1=223y_{1} = 2 \sqrt[3]{2}
=
2232 \sqrt[3]{2}
=
2.51984209978975
x2=(23233i)24x_{2} = \frac{\left(- \sqrt[3]{2} - \sqrt[3]{2} \sqrt{3} i\right)^{2}}{4}
=
223(1+3i)2\frac{2^{\frac{2}{3}} \left(-1 + \sqrt{3} i\right)}{2}
=
-0.7937005259841 + 1.3747296369986*i

y2=23233iy_{2} = - \sqrt[3]{2} - \sqrt[3]{2} \sqrt{3} i
=
23(1+3i)- \sqrt[3]{2} \left(1 + \sqrt{3} i\right)
=
-1.25992104989487 - 2.18224727194344*i
x3=(23+233i)24x_{3} = \frac{\left(- \sqrt[3]{2} + \sqrt[3]{2} \sqrt{3} i\right)^{2}}{4}
=
223(13i)24\frac{2^{\frac{2}{3}} \left(1 - \sqrt{3} i\right)^{2}}{4}
=
-0.7937005259841 - 1.3747296369986*i

y3=23+233iy_{3} = - \sqrt[3]{2} + \sqrt[3]{2} \sqrt{3} i
=
23(1+3i)\sqrt[3]{2} \left(-1 + \sqrt{3} i\right)
=
-1.25992104989487 + 2.18224727194344*i
Respuesta numérica [src]
x1 = 1.587401051968199
y1 = 2.519842099789746
x1 = 1.587401051968199
y1 = 2.519842099789746