kx+y=b; kx+by=c

Ha introducido [src]

k*x + y = b

$$k x + y = b$$

k*x + b*y = c

$$b y + k x = c$$

b*y + k*x = c

Respuesta rápida

$$b_{1} = k x + y$$
=
$$k x + y$$
=

y + k*x

$$c_{1} = k x y + k x + y^{2}$$
=
$$k x y + k x + y^{2}$$
=

y^2 + k*x + k*x*y