Solución detallada
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No logro encontrar los pasos en la búsqueda de esta derivada.
Perola derivada
Respuesta:
x / 2*x*sin(2*x - 1) \
cos (2*x - 1)*|- ---------------- + log(cos(2*x - 1))|
\ cos(2*x - 1) /
$$\left(- \frac{2 x \sin{\left(2 x - 1 \right)}}{\cos{\left(2 x - 1 \right)}} + \log{\left(\cos{\left(2 x - 1 \right)} \right)}\right) \cos^{x}{\left(2 x - 1 \right)}$$
/ 2 2 \
x |/ 2*x*sin(-1 + 2*x)\ 4*sin(-1 + 2*x) 4*x*sin (-1 + 2*x)|
cos (-1 + 2*x)*||-log(cos(-1 + 2*x)) + -----------------| - 4*x - --------------- - ------------------|
|\ cos(-1 + 2*x) / cos(-1 + 2*x) 2 |
\ cos (-1 + 2*x) /
$$\left(- \frac{4 x \sin^{2}{\left(2 x - 1 \right)}}{\cos^{2}{\left(2 x - 1 \right)}} - 4 x + \left(\frac{2 x \sin{\left(2 x - 1 \right)}}{\cos{\left(2 x - 1 \right)}} - \log{\left(\cos{\left(2 x - 1 \right)} \right)}\right)^{2} - \frac{4 \sin{\left(2 x - 1 \right)}}{\cos{\left(2 x - 1 \right)}}\right) \cos^{x}{\left(2 x - 1 \right)}$$
/ 3 2 / 2 \ 3 \
x | / 2*x*sin(-1 + 2*x)\ 12*sin (-1 + 2*x) / 2*x*sin(-1 + 2*x)\ | sin(-1 + 2*x) x*sin (-1 + 2*x)| 16*x*sin(-1 + 2*x) 16*x*sin (-1 + 2*x)|
cos (-1 + 2*x)*|-12 - |-log(cos(-1 + 2*x)) + -----------------| - ----------------- + 12*|-log(cos(-1 + 2*x)) + -----------------|*|x + ------------- + ----------------| - ------------------ - -------------------|
| \ cos(-1 + 2*x) / 2 \ cos(-1 + 2*x) / | cos(-1 + 2*x) 2 | cos(-1 + 2*x) 3 |
\ cos (-1 + 2*x) \ cos (-1 + 2*x) / cos (-1 + 2*x) /
$$\left(- \frac{16 x \sin^{3}{\left(2 x - 1 \right)}}{\cos^{3}{\left(2 x - 1 \right)}} - \frac{16 x \sin{\left(2 x - 1 \right)}}{\cos{\left(2 x - 1 \right)}} - \left(\frac{2 x \sin{\left(2 x - 1 \right)}}{\cos{\left(2 x - 1 \right)}} - \log{\left(\cos{\left(2 x - 1 \right)} \right)}\right)^{3} + 12 \left(\frac{2 x \sin{\left(2 x - 1 \right)}}{\cos{\left(2 x - 1 \right)}} - \log{\left(\cos{\left(2 x - 1 \right)} \right)}\right) \left(\frac{x \sin^{2}{\left(2 x - 1 \right)}}{\cos^{2}{\left(2 x - 1 \right)}} + x + \frac{\sin{\left(2 x - 1 \right)}}{\cos{\left(2 x - 1 \right)}}\right) - \frac{12 \sin^{2}{\left(2 x - 1 \right)}}{\cos^{2}{\left(2 x - 1 \right)}} - 12\right) \cos^{x}{\left(2 x - 1 \right)}$$