x x E *10
E^x*10^x
Se aplica la regla de la derivada de una multiplicación:
ddxf(x)g(x)=f(x)ddxg(x)+g(x)ddxf(x)\frac{d}{d x} f{\left(x \right)} g{\left(x \right)} = f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}dxdf(x)g(x)=f(x)dxdg(x)+g(x)dxdf(x)
f(x)=exf{\left(x \right)} = e^{x}f(x)=ex; calculamos ddxf(x)\frac{d}{d x} f{\left(x \right)}dxdf(x):
Derivado exe^{x}ex es.
g(x)=10xg{\left(x \right)} = 10^{x}g(x)=10x; calculamos ddxg(x)\frac{d}{d x} g{\left(x \right)}dxdg(x):
ddx10x=10xlog(10)\frac{d}{d x} 10^{x} = 10^{x} \log{\left(10 \right)}dxd10x=10xlog(10)
Como resultado de: 10xex+10xexlog(10)10^{x} e^{x} + 10^{x} e^{x} \log{\left(10 \right)}10xex+10xexlog(10)
Simplificamos:
(10e)x(1+log(10))\left(10 e\right)^{x} \left(1 + \log{\left(10 \right)}\right)(10e)x(1+log(10))
Respuesta:
x x x x 10 *e + 10 *e *log(10)
x / 2 \ x 10 *\1 + log (10) + 2*log(10)/*e
x / 3 2 \ x 10 *\1 + log (10) + 3*log (10) + 3*log(10)/*e