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Derivada de y=6x^4-2x^3+11x^2-3x+5,x0=-1

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Solución

Ha introducido [src]
    4      3       2               
(6*x  - 2*x  + 11*x  - 3*x + 5, x0)
4 3 2 (6*x - 2*x + 11*x - 3*x + 5, x0)
(-3*x + 11*x^2 + 6*x^4 - 2*x^3 + 5, x0)
Primera derivada [src]
d /    4      3       2               \
--\(6*x  - 2*x  + 11*x  - 3*x + 5, x0)/
dx                                     
$$\frac{\partial}{\partial x} \left( \left(- 3 x + \left(11 x^{2} + \left(6 x^{4} - 2 x^{3}\right)\right)\right) + 5, \ x_{0}\right)$$
Segunda derivada [src]
  2                                     
 d /    4      3       2               \
---\(6*x  - 2*x  + 11*x  - 3*x + 5, x0)/
  2                                     
dx                                      
$$\frac{\partial^{2}}{\partial x^{2}} \left( \left(- 3 x + \left(11 x^{2} + \left(6 x^{4} - 2 x^{3}\right)\right)\right) + 5, \ x_{0}\right)$$
Tercera derivada [src]
  3                                     
 d /    4      3       2               \
---\(6*x  - 2*x  + 11*x  - 3*x + 5, x0)/
  3                                     
dx                                      
$$\frac{\partial^{3}}{\partial x^{3}} \left( \left(- 3 x + \left(11 x^{2} + \left(6 x^{4} - 2 x^{3}\right)\right)\right) + 5, \ x_{0}\right)$$