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Ecuación diferencial y''+6y'+13y=13x^2+38x+14

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

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Solución

Ha introducido [src]
                         2                          
  d                     d                   2       
6*--(y(x)) + 13*y(x) + ---(y(x)) = 14 + 13*x  + 38*x
  dx                     2                          
                       dx                           
$$13 y{\left(x \right)} + 6 \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)} = 13 x^{2} + 38 x + 14$$
13*y + 6*y' + y'' = 13*x^2 + 38*x + 14
Respuesta [src]
        2                                      -3*x
y(x) = x  + 2*x + (C1*sin(2*x) + C2*cos(2*x))*e    
$$y{\left(x \right)} = x^{2} + 2 x + \left(C_{1} \sin{\left(2 x \right)} + C_{2} \cos{\left(2 x \right)}\right) e^{- 3 x}$$
Clasificación
nth linear constant coeff undetermined coefficients
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