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Ecuación diferencial y"-4y'+29y=x^2

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

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Solución

Ha introducido [src]
                           2           
    d                     d           2
- 4*--(y(x)) + 29*y(x) + ---(y(x)) = x 
    dx                     2           
                         dx            
$$29 y{\left(x \right)} - 4 \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)} = x^{2}$$
29*y - 4*y' + y'' = x^2
Respuesta [src]
                  2                                         
           26    x    8*x                                2*x
y(x) = - ----- + -- + --- + (C1*sin(5*x) + C2*cos(5*x))*e   
         24389   29   841                                   
$$y{\left(x \right)} = \frac{x^{2}}{29} + \frac{8 x}{841} + \left(C_{1} \sin{\left(5 x \right)} + C_{2} \cos{\left(5 x \right)}\right) e^{2 x} - \frac{26}{24389}$$
Clasificación
nth linear constant coeff undetermined coefficients
nth linear constant coeff variation of parameters
nth linear constant coeff variation of parameters Integral