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Ecuación diferencial y''-2y'+10y=10x^2+4x+3

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

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Solución

Ha introducido [src]
                           2                        
    d                     d                        2
- 2*--(y(x)) + 10*y(x) + ---(y(x)) = 3 + 4*x + 10*x 
    dx                     2                        
                         dx                         
$$10 y{\left(x \right)} - 2 \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)} = 10 x^{2} + 4 x + 3$$
10*y - 2*y' + y'' = 10*x^2 + 4*x + 3
Respuesta [src]
       13    2   4*x                                x
y(x) = -- + x  + --- + (C1*sin(3*x) + C2*cos(3*x))*e 
       50         5                                  
$$y{\left(x \right)} = x^{2} + \frac{4 x}{5} + \left(C_{1} \sin{\left(3 x \right)} + C_{2} \cos{\left(3 x \right)}\right) e^{x} + \frac{13}{50}$$
Clasificación
nth linear constant coeff undetermined coefficients
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nth linear constant coeff variation of parameters Integral