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Ecuación diferencial y'''-2y''+2y'=2*x+15cos(x)

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

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Solución

Ha introducido [src]
      2                        3                        
     d            d           d                         
- 2*---(y(x)) + 2*--(y(x)) + ---(y(x)) = 2*x + 15*cos(x)
      2           dx           3                        
    dx                       dx                         
$$2 \frac{d}{d x} y{\left(x \right)} - 2 \frac{d^{2}}{d x^{2}} y{\left(x \right)} + \frac{d^{3}}{d x^{3}} y{\left(x \right)} = 2 x + 15 \cos{\left(x \right)}$$
2*y' - 2*y'' + y''' = 2*x + 15*cos(x)
Respuesta [src]
                 2                                                   
                x                                                   x
y(x) = C1 + x + -- + 3*sin(x) + 6*cos(x) + (C2*sin(x) + C3*cos(x))*e 
                2                                                    
$$y{\left(x \right)} = C_{1} + \frac{x^{2}}{2} + x + \left(C_{2} \sin{\left(x \right)} + C_{3} \cos{\left(x \right)}\right) e^{x} + 3 \sin{\left(x \right)} + 6 \cos{\left(x \right)}$$
Clasificación
nth linear constant coeff undetermined coefficients
nth linear constant coeff variation of parameters
nth order reducible
nth linear constant coeff variation of parameters Integral