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Ecuación diferencial 2y'''-2y''+2y'-2y=-2x-4

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
      2                                   3                 
     d                     d             d                  
- 2*---(y(x)) - 2*y(x) + 2*--(y(x)) + 2*---(y(x)) = -4 - 2*x
      2                    dx             3                 
    dx                                  dx                  
$$- 2 y{\left(x \right)} + 2 \frac{d}{d x} y{\left(x \right)} - 2 \frac{d^{2}}{d x^{2}} y{\left(x \right)} + 2 \frac{d^{3}}{d x^{3}} y{\left(x \right)} = - 2 x - 4$$
-2*y + 2*y' - 2*y'' + 2*y''' = -2*x - 4
Respuesta [src]
                   x                        
y(x) = 3 + x + C1*e  + C2*sin(x) + C3*cos(x)
$$y{\left(x \right)} = C_{1} e^{x} + C_{2} \sin{\left(x \right)} + C_{3} \cos{\left(x \right)} + x + 3$$
Clasificación
nth linear constant coeff undetermined coefficients
nth linear constant coeff variation of parameters
nth linear constant coeff variation of parameters Integral