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Ecuación diferencial y'''+3y''+3y'+y=x^2

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

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Solución

Ha introducido [src]
                 2           3                  
  d             d           d                  2
3*--(y(x)) + 3*---(y(x)) + ---(y(x)) + y(x) = x 
  dx             2           3                  
               dx          dx                   
$$y{\left(x \right)} + 3 \frac{d}{d x} y{\left(x \right)} + 3 \frac{d^{2}}{d x^{2}} y{\left(x \right)} + \frac{d^{3}}{d x^{3}} y{\left(x \right)} = x^{2}$$
y + 3*y' + 3*y'' + y''' = x^2
Respuesta [src]
             2                               -x
y(x) = 12 + x  - 6*x + (C1 + x*(C2 + C3*x))*e  
$$y{\left(x \right)} = x^{2} - 6 x + \left(C_{1} + x \left(C_{2} + C_{3} x\right)\right) e^{- x} + 12$$
Clasificación
nth linear constant coeff undetermined coefficients
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