Sr Examen
Ecuación diferencial y''-6y'+9y=(9x^2+6x+2)/(x^3(3x-2))
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
2 2
d d 2 + 6*x + 9*x
- 6*--(y(x)) + 9*y(x) + ---(y(x)) = --------------
dx 2 3
dx x *(-2 + 3*x)
$$9 y{\left(x \right)} - 6 \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)} = \frac{9 x^{2} + 6 x + 2}{x^{3} \left(3 x - 2\right)}$$
9*y - 6*y' + y'' = (9*x^2 + 6*x + 2)/(x^3*(3*x - 2))
Clasificación
nth linear constant coeff variation of parameters
nth linear constant coeff variation of parameters Integral