sin((p+2*x)/3)=sin((-2*p+x)/3) la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
/ -I*p\
x1 = 3*arg\e / - 3*I*im(p)
$$x_{1} = - 3 i \operatorname{im}{\left(p\right)} + 3 \arg{\left(e^{- i p} \right)}$$
/ I*p\
| ---|
I*im(p) | 3 |
x2 = ------- + arg\-e /
3
$$x_{2} = \frac{i \operatorname{im}{\left(p\right)}}{3} + \arg{\left(- e^{\frac{i p}{3}} \right)}$$
x2 = i*im(p)/3 + arg(-exp(i*p/3))
Suma y producto de raíces
[src]
/ I*p\
| ---|
/ -I*p\ I*im(p) | 3 |
3*arg\e / - 3*I*im(p) + ------- + arg\-e /
3
$$\left(- 3 i \operatorname{im}{\left(p\right)} + 3 \arg{\left(e^{- i p} \right)}\right) + \left(\frac{i \operatorname{im}{\left(p\right)}}{3} + \arg{\left(- e^{\frac{i p}{3}} \right)}\right)$$
/ I*p\
| ---|
/ -I*p\ 8*I*im(p) | 3 |
3*arg\e / - --------- + arg\-e /
3
$$- \frac{8 i \operatorname{im}{\left(p\right)}}{3} + 3 \arg{\left(e^{- i p} \right)} + \arg{\left(- e^{\frac{i p}{3}} \right)}$$
/ / I*p\\
| | ---||
/ / -I*p\ \ |I*im(p) | 3 ||
\3*arg\e / - 3*I*im(p)/*|------- + arg\-e /|
\ 3 /
$$\left(- 3 i \operatorname{im}{\left(p\right)} + 3 \arg{\left(e^{- i p} \right)}\right) \left(\frac{i \operatorname{im}{\left(p\right)}}{3} + \arg{\left(- e^{\frac{i p}{3}} \right)}\right)$$
/ / I*p\ \
| | ---| |
/ / -I*p\ \ | | 3 | |
-\- arg\e / + I*im(p)/*\3*arg\-e / + I*im(p)/
$$- \left(i \operatorname{im}{\left(p\right)} - \arg{\left(e^{- i p} \right)}\right) \left(i \operatorname{im}{\left(p\right)} + 3 \arg{\left(- e^{\frac{i p}{3}} \right)}\right)$$
-(-arg(exp(-i*p)) + i*im(p))*(3*arg(-exp(i*p/3)) + i*im(p))