ln(y)=3*x+c la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
Tenemos la ecuación
log(y)=c+3xlog(y)=c+3xEs la ecuación de la forma:
log(v)=p
Por definición log
v=e^p
entonces
y=e1c+3xsimplificamos
y=ec+3x
Suma y producto de raíces
[src]
3*re(x) + re(c) 3*re(x) + re(c)
cos(3*im(x) + im(c))*e + I*e *sin(3*im(x) + im(c))
iere(c)+3re(x)sin(im(c)+3im(x))+ere(c)+3re(x)cos(im(c)+3im(x))
3*re(x) + re(c) 3*re(x) + re(c)
cos(3*im(x) + im(c))*e + I*e *sin(3*im(x) + im(c))
iere(c)+3re(x)sin(im(c)+3im(x))+ere(c)+3re(x)cos(im(c)+3im(x))
3*re(x) + re(c) 3*re(x) + re(c)
cos(3*im(x) + im(c))*e + I*e *sin(3*im(x) + im(c))
iere(c)+3re(x)sin(im(c)+3im(x))+ere(c)+3re(x)cos(im(c)+3im(x))
3*re(x) + I*(3*im(x) + im(c)) + re(c)
e
ei(im(c)+3im(x))+re(c)+3re(x)
exp(3*re(x) + i*(3*im(x) + im(c)) + re(c))
3*re(x) + re(c) 3*re(x) + re(c)
y1 = cos(3*im(x) + im(c))*e + I*e *sin(3*im(x) + im(c))
y1=iere(c)+3re(x)sin(im(c)+3im(x))+ere(c)+3re(x)cos(im(c)+3im(x))
y1 = i*exp(re(c) + 3*re(x))*sin(im(c) + 3*im(x)) + exp(re(c) + 3*re(x))*cos(im(c) + 3*im(x))