x^3+y^3 la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Teorema de Cardano-Vieta
es ecuación cúbica reducida
py2+qy+v+y3=0donde
p=abp=0q=acq=0v=adv=x3Fórmulas de Cardano-Vieta
y1+y2+y3=−py1y2+y1y3+y2y3=qy1y2y3=vy1+y2+y3=0y1y2+y1y3+y2y3=0y1y2y3=x3
y1=−re(x)−iim(x)
/ ___ \ ___
re(x) |im(x) \/ 3 *re(x)| \/ 3 *im(x)
y2 = ----- + I*|----- - -----------| + -----------
2 \ 2 2 / 2
y2=i(−23re(x)+2im(x))+2re(x)+23im(x)
/ ___ \ ___
re(x) |im(x) \/ 3 *re(x)| \/ 3 *im(x)
y3 = ----- + I*|----- + -----------| - -----------
2 \ 2 2 / 2
y3=i(23re(x)+2im(x))+2re(x)−23im(x)
y3 = i*(sqrt(3)*re(x)/2 + im(x)/2) + re(x)/2 - sqrt(3)*im(x)/2
Suma y producto de raíces
[src]
/ ___ \ ___ / ___ \ ___
re(x) |im(x) \/ 3 *re(x)| \/ 3 *im(x) re(x) |im(x) \/ 3 *re(x)| \/ 3 *im(x)
-re(x) - I*im(x) + ----- + I*|----- - -----------| + ----------- + ----- + I*|----- + -----------| - -----------
2 \ 2 2 / 2 2 \ 2 2 / 2
((−re(x)−iim(x))+(i(−23re(x)+2im(x))+2re(x)+23im(x)))+(i(23re(x)+2im(x))+2re(x)−23im(x))
/ ___ \ / ___ \
|im(x) \/ 3 *re(x)| |im(x) \/ 3 *re(x)|
I*|----- + -----------| + I*|----- - -----------| - I*im(x)
\ 2 2 / \ 2 2 /
i(−23re(x)+2im(x))+i(23re(x)+2im(x))−iim(x)
/ / ___ \ ___ \ / / ___ \ ___ \
|re(x) |im(x) \/ 3 *re(x)| \/ 3 *im(x)| |re(x) |im(x) \/ 3 *re(x)| \/ 3 *im(x)|
(-re(x) - I*im(x))*|----- + I*|----- - -----------| + -----------|*|----- + I*|----- + -----------| - -----------|
\ 2 \ 2 2 / 2 / \ 2 \ 2 2 / 2 /
(−re(x)−iim(x))(i(−23re(x)+2im(x))+2re(x)+23im(x))(i(23re(x)+2im(x))+2re(x)−23im(x))
3 3 2 2
- re (x) + I*im (x) + 3*im (x)*re(x) - 3*I*re (x)*im(x)
−(re(x))3−3i(re(x))2im(x)+3re(x)(im(x))2+i(im(x))3
-re(x)^3 + i*im(x)^3 + 3*im(x)^2*re(x) - 3*i*re(x)^2*im(x)