sin(x-y)=cos(x+y) la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Suma y producto de raíces
[src]
pi 3*pi / -I*x\ / I*x\
- -- + ---- + -I*im(x) + arg\-e / + I*im(x) + arg\-e /
4 4
$$\left(i \operatorname{im}{\left(x\right)} + \arg{\left(- e^{i x} \right)}\right) + \left(\left(- i \operatorname{im}{\left(x\right)} + \arg{\left(- e^{- i x} \right)}\right) + \left(- \frac{\pi}{4} + \frac{3 \pi}{4}\right)\right)$$
pi / I*x\ / -I*x\
-- + arg\-e / + arg\-e /
2
$$\arg{\left(- e^{- i x} \right)} + \arg{\left(- e^{i x} \right)} + \frac{\pi}{2}$$
-pi 3*pi / / -I*x\\ / / I*x\\
----*----*\-I*im(x) + arg\-e //*\I*im(x) + arg\-e //
4 4
$$- \frac{\pi}{4} \frac{3 \pi}{4} \left(- i \operatorname{im}{\left(x\right)} + \arg{\left(- e^{- i x} \right)}\right) \left(i \operatorname{im}{\left(x\right)} + \arg{\left(- e^{i x} \right)}\right)$$
2 / / -I*x\ \ / / I*x\\
3*pi *\- arg\-e / + I*im(x)/*\I*im(x) + arg\-e //
------------------------------------------------------
16
$$\frac{3 \pi^{2} \left(i \operatorname{im}{\left(x\right)} - \arg{\left(- e^{- i x} \right)}\right) \left(i \operatorname{im}{\left(x\right)} + \arg{\left(- e^{i x} \right)}\right)}{16}$$
3*pi^2*(-arg(-exp(-i*x)) + i*im(x))*(i*im(x) + arg(-exp(i*x)))/16
$$y_{1} = - \frac{\pi}{4}$$
$$y_{2} = \frac{3 \pi}{4}$$
/ -I*x\
y3 = -I*im(x) + arg\-e /
$$y_{3} = - i \operatorname{im}{\left(x\right)} + \arg{\left(- e^{- i x} \right)}$$
/ I*x\
y4 = I*im(x) + arg\-e /
$$y_{4} = i \operatorname{im}{\left(x\right)} + \arg{\left(- e^{i x} \right)}$$
y4 = i*im(x) + arg(-exp(i*x))