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2tg^3x-2tg^2x+3tgx-3=0 la ecuación

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Solución numérica:

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Solución

Ha introducido [src]
     3           2                      
2*tan (x) - 2*tan (x) + 3*tan(x) - 3 = 0
$$\left(\left(2 \tan^{3}{\left(x \right)} - 2 \tan^{2}{\left(x \right)}\right) + 3 \tan{\left(x \right)}\right) - 3 = 0$$
Solución detallada
Tenemos la ecuación
$$\left(\left(2 \tan^{3}{\left(x \right)} - 2 \tan^{2}{\left(x \right)}\right) + 3 \tan{\left(x \right)}\right) - 3 = 0$$
cambiamos
$$2 \tan^{3}{\left(x \right)} - 2 \tan^{2}{\left(x \right)} + 3 \tan{\left(x \right)} - 3 = 0$$
$$\left(\left(2 \tan^{3}{\left(x \right)} - 2 \tan^{2}{\left(x \right)}\right) + 3 \tan{\left(x \right)}\right) - 3 = 0$$
Sustituimos
$$w = \tan{\left(x \right)}$$
Tenemos la ecuación:
$$2 w^{3} - 2 w^{2} + 3 w - 3 = 0$$
cambiamos
$$\left(3 w + \left(\left(- 2 w^{2} + \left(2 w^{3} - 2\right)\right) + 2\right)\right) - 3 = 0$$
o
$$\left(3 w + \left(\left(- 2 w^{2} + \left(2 w^{3} - 2 \cdot 1^{3}\right)\right) + 2 \cdot 1^{2}\right)\right) - 3 = 0$$
$$3 \left(w - 1\right) + \left(- 2 \left(w^{2} - 1^{2}\right) + 2 \left(w^{3} - 1^{3}\right)\right) = 0$$
$$3 \left(w - 1\right) + \left(- 2 \left(w - 1\right) \left(w + 1\right) + 2 \left(w - 1\right) \left(\left(w^{2} + w\right) + 1^{2}\right)\right) = 0$$
Saquemos el factor común -1 + w fuera de paréntesis
obtendremos:
$$\left(w - 1\right) \left(\left(- 2 \left(w + 1\right) + 2 \left(\left(w^{2} + w\right) + 1^{2}\right)\right) + 3\right) = 0$$
o
$$\left(w - 1\right) \left(2 w^{2} + 3\right) = 0$$
entonces:
$$w_{1} = 1$$
y además
obtenemos la ecuación
$$2 w^{2} + 3 = 0$$
Es la ecuación de la forma
a*w^2 + b*w + c = 0

La ecuación cuadrática puede ser resuelta
con la ayuda del discriminante.
Las raíces de la ecuación cuadrática:
$$w_{2} = \frac{\sqrt{D} - b}{2 a}$$
$$w_{3} = \frac{- \sqrt{D} - b}{2 a}$$
donde D = b^2 - 4*a*c es el discriminante.
Como
$$a = 2$$
$$b = 0$$
$$c = 3$$
, entonces
D = b^2 - 4 * a * c = 

(0)^2 - 4 * (2) * (3) = -24

Como D < 0 la ecuación
no tiene raíces reales,
pero hay raíces complejas.
w2 = (-b + sqrt(D)) / (2*a)

w3 = (-b - sqrt(D)) / (2*a)

o
$$w_{2} = \frac{\sqrt{6} i}{2}$$
$$w_{3} = - \frac{\sqrt{6} i}{2}$$
Entonces la respuesta definitiva es para 2*tan(x)^3 - 2*tan(x)^2 + 3*tan(x) - 3 = 0:
$$w_{1} = 1$$
$$w_{2} = \frac{\sqrt{6} i}{2}$$
$$w_{3} = - \frac{\sqrt{6} i}{2}$$
hacemos cambio inverso
$$\tan{\left(x \right)} = w$$
Tenemos la ecuación
$$\tan{\left(x \right)} = w$$
es la ecuación trigonométrica más simple
Esta ecuación se reorganiza en
$$x = \pi n + \operatorname{atan}{\left(w \right)}$$
O
$$x = \pi n + \operatorname{atan}{\left(w \right)}$$
, donde n es cualquier número entero
sustituimos w:
$$x_{1} = \pi n + \operatorname{atan}{\left(w_{1} \right)}$$
$$x_{1} = \pi n + \operatorname{atan}{\left(1 \right)}$$
$$x_{1} = \pi n + \frac{\pi}{4}$$
$$x_{2} = \pi n + \operatorname{atan}{\left(w_{2} \right)}$$
$$x_{2} = \pi n + \operatorname{atan}{\left(\frac{\sqrt{6} i}{2} \right)}$$
$$x_{2} = \pi n + i \operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}$$
$$x_{3} = \pi n + \operatorname{atan}{\left(w_{3} \right)}$$
$$x_{3} = \pi n + \operatorname{atan}{\left(- \frac{\sqrt{6} i}{2} \right)}$$
$$x_{3} = \pi n - i \operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}$$
Gráfica
Respuesta rápida [src]
     pi
x1 = --
     4 
$$x_{1} = \frac{\pi}{4}$$
           /     /  ___\\     /     /  ___\\
           |     |\/ 6 ||     |     |\/ 6 ||
x2 = - I*re|atanh|-----|| + im|atanh|-----||
           \     \  2  //     \     \  2  //
$$x_{2} = \operatorname{im}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)} - i \operatorname{re}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)}$$
         /     /  ___\\       /     /  ___\\
         |     |\/ 6 ||       |     |\/ 6 ||
x3 = - im|atanh|-----|| + I*re|atanh|-----||
         \     \  2  //       \     \  2  //
$$x_{3} = - \operatorname{im}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)} + i \operatorname{re}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)}$$
x3 = -im(atanh(sqrt(6)/2)) + i*re(atanh(sqrt(6)/2))
Suma y producto de raíces [src]
suma
           /     /  ___\\     /     /  ___\\       /     /  ___\\       /     /  ___\\
pi         |     |\/ 6 ||     |     |\/ 6 ||       |     |\/ 6 ||       |     |\/ 6 ||
-- + - I*re|atanh|-----|| + im|atanh|-----|| + - im|atanh|-----|| + I*re|atanh|-----||
4          \     \  2  //     \     \  2  //       \     \  2  //       \     \  2  //
$$\left(\frac{\pi}{4} + \left(\operatorname{im}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)} - i \operatorname{re}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)}\right)\right) + \left(- \operatorname{im}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)} + i \operatorname{re}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)}\right)$$
=
pi
--
4 
$$\frac{\pi}{4}$$
producto
   /      /     /  ___\\     /     /  ___\\\ /    /     /  ___\\       /     /  ___\\\
pi |      |     |\/ 6 ||     |     |\/ 6 ||| |    |     |\/ 6 ||       |     |\/ 6 |||
--*|- I*re|atanh|-----|| + im|atanh|-----|||*|- im|atanh|-----|| + I*re|atanh|-----|||
4  \      \     \  2  //     \     \  2  /// \    \     \  2  //       \     \  2  ///
$$\frac{\pi}{4} \left(\operatorname{im}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)} - i \operatorname{re}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)}\right) \left(- \operatorname{im}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)} + i \operatorname{re}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)}\right)$$
=
                                             2 
    /      /     /  ___\\     /     /  ___\\\  
    |      |     |\/ 6 ||     |     |\/ 6 |||  
-pi*|- I*re|atanh|-----|| + im|atanh|-----|||  
    \      \     \  2  //     \     \  2  ///  
-----------------------------------------------
                       4                       
$$- \frac{\pi \left(\operatorname{im}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)} - i \operatorname{re}{\left(\operatorname{atanh}{\left(\frac{\sqrt{6}}{2} \right)}\right)}\right)^{2}}{4}$$
-pi*(-i*re(atanh(sqrt(6)/2)) + im(atanh(sqrt(6)/2)))^2/4
Respuesta numérica [src]
x1 = -36.9137136796801
x2 = 51.0508806208341
x3 = -74.6128255227576
x4 = -84.037603483527
x5 = 22.776546738526
x6 = 3.92699081698724
x7 = -96.6039740978861
x8 = -43.1968989868597
x9 = -33.7721210260903
x10 = 10.2101761241668
x11 = 16.4933614313464
x12 = -8.63937979737193
x13 = 19.6349540849362
x14 = 44.7676953136546
x15 = 13.3517687777566
x16 = 47.9092879672443
x17 = 29.0597320457056
x18 = 60.4756585816035
x19 = -99.7455667514759
x20 = 25.9181393921158
x21 = 85.6083998103219
x22 = -80.8960108299372
x23 = -11.7809724509617
x24 = -62.0464549083984
x25 = 76.1836218495525
x26 = 69.9004365423729
x27 = -2.35619449019234
x28 = -68.329640215578
x29 = -55.7632696012188
x30 = -65.1880475619882
x31 = -14.9225651045515
x32 = 82.4668071567321
x33 = -18.0641577581413
x34 = 63.6172512351933
x35 = 32.2013246992954
x36 = 54.1924732744239
x37 = -40.0553063332699
x38 = -49.4800842940392
x39 = 7.06858347057703
x40 = 98.174770424681
x41 = 41.6261026600648
x42 = -58.9048622548086
x43 = 101.316363078271
x44 = 0.785398163397448
x45 = 88.7499924639117
x46 = -24.3473430653209
x47 = -46.3384916404494
x48 = -77.7544181763474
x49 = -93.4623814442964
x50 = 57.3340659280137
x51 = -87.1791961371168
x52 = 95.0331777710912
x53 = -52.621676947629
x54 = -5.49778714378214
x55 = 79.3252145031423
x56 = 35.3429173528852
x57 = -90.3207887907066
x58 = 38.484510006475
x59 = 91.8915851175014
x60 = -27.4889357189107
x61 = 73.0420291959627
x62 = -21.2057504117311
x63 = 66.7588438887831
x64 = -71.4712328691678
x65 = -30.6305283725005
x65 = -30.6305283725005