log3x=1/3log38-2log320-3log32 la ecuación
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Solución
Solución detallada
Tenemos la ecuación
$$\log{\left(3 x \right)} = - 3 \log{\left(32 \right)} + \left(- 2 \log{\left(320 \right)} + \frac{\log{\left(38 \right)}}{3}\right)$$
$$\log{\left(3 x \right)} = - 2 \log{\left(320 \right)} - 3 \log{\left(32 \right)} + \frac{\log{\left(38 \right)}}{3}$$
Es la ecuación de la forma:
log(v)=p
Por definición log
v=e^p
entonces
$$3 x = e^{\frac{- 2 \log{\left(320 \right)} - 3 \log{\left(32 \right)} + \frac{\log{\left(38 \right)}}{3}}{1}}$$
simplificamos
$$3 x = \frac{\sqrt[3]{38}}{3355443200}$$
$$x = \frac{\sqrt[3]{38}}{10066329600}$$
3 ____
\/ 38
x1 = -----------
10066329600
$$x_{1} = \frac{\sqrt[3]{38}}{10066329600}$$
x1 = 38^(1/3)/10066329600
Suma y producto de raíces
[src]
3 ____
\/ 38
-----------
10066329600
$$\frac{\sqrt[3]{38}}{10066329600}$$
3 ____
\/ 38
-----------
10066329600
$$\frac{\sqrt[3]{38}}{10066329600}$$
3 ____
\/ 38
-----------
10066329600
$$\frac{\sqrt[3]{38}}{10066329600}$$
3 ____
\/ 38
-----------
10066329600
$$\frac{\sqrt[3]{38}}{10066329600}$$
x1 = 3.33982249776419e-10
x1 = 3.33982249776419e-10