Tomamos como el límite
$$\lim_{x \to 0^+}\left(\frac{- \frac{x}{e^{2}} + e^{3} x}{x}\right)$$
cambiamos
$$\lim_{x \to 0^+}\left(\frac{- \frac{x}{e^{2}} + e^{3} x}{x}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{x \left(-1 + e\right) \left(1 + e + e^{2} + e^{3} + e^{4}\right) e^{-2}}{x}\right)$$
=
$$\lim_{x \to 0^+}\left(- \frac{1 - e^{5}}{e^{2}}\right) = $$
$$- \frac{1 - e^{5}}{e^{2}} = $$
= -(1 - exp(5))*exp(-2)
Entonces la respuesta definitiva es:
$$\lim_{x \to 0^+}\left(\frac{- \frac{x}{e^{2}} + e^{3} x}{x}\right) = - \frac{1 - e^{5}}{e^{2}}$$