Expresión ((!a)&b&c)v(a&b&(!c))
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Solución
Solución detallada
$$\left(a \wedge b \wedge \neg c\right) \vee \left(b \wedge c \wedge \neg a\right) = b \wedge \left(a \vee c\right) \wedge \left(\neg a \vee \neg c\right)$$
$$b \wedge \left(a \vee c\right) \wedge \left(\neg a \vee \neg c\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
$$\left(a \wedge b \wedge \neg c\right) \vee \left(b \wedge c \wedge \neg a\right)$$
Ya está reducido a FNC
$$b \wedge \left(a \vee c\right) \wedge \left(\neg a \vee \neg c\right)$$
$$\left(a \wedge b \wedge \neg a\right) \vee \left(a \wedge b \wedge \neg c\right) \vee \left(b \wedge c \wedge \neg a\right) \vee \left(b \wedge c \wedge \neg c\right)$$
(a∧b∧(¬a))∨(a∧b∧(¬c))∨(b∧c∧(¬a))∨(b∧c∧(¬c))
$$b \wedge \left(a \vee c\right) \wedge \left(\neg a \vee \neg c\right)$$