Sr Examen
Lógica matemática/ notA+notB*C*notD

Expresión notA+notB*C*notD

El profesor se sorprenderá mucho al ver tu solución correcta😉

⌨

    Solución

    Ha introducido [src] 
    (¬a)∨(c∧(¬b)∧(¬d))
    $$\left(c \wedge \neg b \wedge \neg d\right) \vee \neg a$$
    Simplificación [src]
    $$\left(c \wedge \neg b \wedge \neg d\right) \vee \neg a$$ 
    (¬a)∨(c∧(¬b)∧(¬d))
    Tabla de verdad 
    +---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 0      |
+---+---+---+---+--------+
    FNC [src]
    $$\left(c \vee \neg a\right) \wedge \left(\neg a \vee \neg b\right) \wedge \left(\neg a \vee \neg d\right)$$ 
    (c∨(¬a))∧((¬a)∨(¬b))∧((¬a)∨(¬d))
    FNCD [src]
    $$\left(c \vee \neg a\right) \wedge \left(\neg a \vee \neg b\right) \wedge \left(\neg a \vee \neg d\right)$$ 
    (c∨(¬a))∧((¬a)∨(¬b))∧((¬a)∨(¬d))
    FND [src]
    Ya está reducido a FND
    $$\left(c \wedge \neg b \wedge \neg d\right) \vee \neg a$$ 
    (¬a)∨(c∧(¬b)∧(¬d))
    FNDP [src]
    $$\left(c \wedge \neg b \wedge \neg d\right) \vee \neg a$$ 
    (¬a)∨(c∧(¬b)∧(¬d))
    © Sr Examen