Sr Examen

Expresión not(A)+not(B)*C*not(D)=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ¬((¬a)∨(c∧(¬b)∧(¬d)))
    ¬((c¬b¬d)¬a)\neg \left(\left(c \wedge \neg b \wedge \neg d\right) \vee \neg a\right)
    Solución detallada
    ¬((c¬b¬d)¬a)=a(bd¬c)\neg \left(\left(c \wedge \neg b \wedge \neg d\right) \vee \neg a\right) = a \wedge \left(b \vee d \vee \neg c\right)
    Simplificación [src]
    a(bd¬c)a \wedge \left(b \vee d \vee \neg c\right)
    a∧(b∨d∨(¬c))
    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | d | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    FNDP [src]
    (ab)(ad)(a¬c)\left(a \wedge b\right) \vee \left(a \wedge d\right) \vee \left(a \wedge \neg c\right)
    (a∧b)∨(a∧d)∨(a∧(¬c))
    FNC [src]
    Ya está reducido a FNC
    a(bd¬c)a \wedge \left(b \vee d \vee \neg c\right)
    a∧(b∨d∨(¬c))
    FNCD [src]
    a(bd¬c)a \wedge \left(b \vee d \vee \neg c\right)
    a∧(b∨d∨(¬c))
    FND [src]
    (ab)(ad)(a¬c)\left(a \wedge b\right) \vee \left(a \wedge d\right) \vee \left(a \wedge \neg c\right)
    (a∧b)∨(a∧d)∨(a∧(¬c))