Sr Examen
Expresión ACD+B¬CD
El profesor se sorprenderá mucho al ver tu solución correcta😉
⌨
Solución
Ha introducido
[src]
(a∧c∧d)∨(b∧d∧(¬c))
$$\left(a \wedge c \wedge d\right) \vee \left(b \wedge d \wedge \neg c\right)$$
Solución detallada
$$\left(a \wedge c \wedge d\right) \vee \left(b \wedge d \wedge \neg c\right) = d \wedge \left(a \vee \neg c\right) \wedge \left(b \vee c\right)$$
Simplificación
[src]
$$d \wedge \left(a \vee \neg c\right) \wedge \left(b \vee c\right)$$
d∧(b∨c)∧(a∨(¬c))
Tabla de verdad
+---+---+---+---+--------+ | a | b | c | d | result | +===+===+===+===+========+ | 0 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 0 | 0 | 1 | 0 | +---+---+---+---+--------+ | 0 | 0 | 1 | 0 | 0 | +---+---+---+---+--------+ | 0 | 0 | 1 | 1 | 0 | +---+---+---+---+--------+ | 0 | 1 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 0 | 1 | 1 | +---+---+---+---+--------+ | 0 | 1 | 1 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 1 | 1 | 0 | +---+---+---+---+--------+ | 1 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 1 | 0 | 0 | 1 | 0 | +---+---+---+---+--------+ | 1 | 0 | 1 | 0 | 0 | +---+---+---+---+--------+ | 1 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 0 | 0 | +---+---+---+---+--------+ | 1 | 1 | 0 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 1 | 0 | 0 | +---+---+---+---+--------+ | 1 | 1 | 1 | 1 | 1 | +---+---+---+---+--------+
FNC
[src]
Ya está reducido a FNC
$$d \wedge \left(a \vee \neg c\right) \wedge \left(b \vee c\right)$$
d∧(b∨c)∧(a∨(¬c))
FND
[src]
$$\left(a \wedge b \wedge d\right) \vee \left(a \wedge c \wedge d\right) \vee \left(b \wedge d \wedge \neg c\right) \vee \left(c \wedge d \wedge \neg c\right)$$
(a∧b∧d)∨(a∧c∧d)∨(b∧d∧(¬c))∨(c∧d∧(¬c))
FNDP
[src]
$$\left(a \wedge c \wedge d\right) \vee \left(b \wedge d \wedge \neg c\right)$$
(a∧c∧d)∨(b∧d∧(¬c))