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Expresión ¬p∨¬q∨p∧q∨¬a

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (¬a)∨(¬p)∨(¬q)∨(p∧q)
    $$\left(p \wedge q\right) \vee \neg a \vee \neg p \vee \neg q$$
    Solución detallada
    $$\left(p \wedge q\right) \vee \neg a \vee \neg p \vee \neg q = 1$$
    Simplificación [src]
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    Tabla de verdad
    +---+---+---+--------+
    | a | p | q | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    1
    1
    FNDP [src]
    1
    1
    FNC [src]
    Ya está reducido a FNC
    1
    1
    FNCD [src]
    1
    1