Sr Examen

Expresión ABC∨¬ABC(¬AB∨AB¬C)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧b∧c)∨(b∧c∧(¬a)∧((b∧(¬a))∨(a∧b∧(¬c))))
    (abc)(bc¬a((b¬a)(ab¬c)))\left(a \wedge b \wedge c\right) \vee \left(b \wedge c \wedge \neg a \wedge \left(\left(b \wedge \neg a\right) \vee \left(a \wedge b \wedge \neg c\right)\right)\right)
    Solución detallada
    (b¬a)(ab¬c)=b(¬a¬c)\left(b \wedge \neg a\right) \vee \left(a \wedge b \wedge \neg c\right) = b \wedge \left(\neg a \vee \neg c\right)
    bc¬a((b¬a)(ab¬c))=bc¬ab \wedge c \wedge \neg a \wedge \left(\left(b \wedge \neg a\right) \vee \left(a \wedge b \wedge \neg c\right)\right) = b \wedge c \wedge \neg a
    (abc)(bc¬a((b¬a)(ab¬c)))=bc\left(a \wedge b \wedge c\right) \vee \left(b \wedge c \wedge \neg a \wedge \left(\left(b \wedge \neg a\right) \vee \left(a \wedge b \wedge \neg c\right)\right)\right) = b \wedge c
    Simplificación [src]
    bcb \wedge c
    b∧c
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    bcb \wedge c
    b∧c
    FND [src]
    Ya está reducido a FND
    bcb \wedge c
    b∧c
    FNCD [src]
    bcb \wedge c
    b∧c
    FNDP [src]
    bcb \wedge c
    b∧c