Sr Examen
Expresión xy¬z∨¬xy¬z∨x¬y
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(x∧(¬y))∨(x∧y∧(¬z))∨(y∧(¬x)∧(¬z))
$$\left(x \wedge \neg y\right) \vee \left(x \wedge y \wedge \neg z\right) \vee \left(y \wedge \neg x \wedge \neg z\right)$$
Solución detallada
$$\left(x \wedge \neg y\right) \vee \left(x \wedge y \wedge \neg z\right) \vee \left(y \wedge \neg x \wedge \neg z\right) = \left(x \wedge \neg y\right) \vee \left(y \wedge \neg z\right)$$
Simplificación
[src]
$$\left(x \wedge \neg y\right) \vee \left(y \wedge \neg z\right)$$
(x∧(¬y))∨(y∧(¬z))
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+
FND
[src]
Ya está reducido a FND
$$\left(x \wedge \neg y\right) \vee \left(y \wedge \neg z\right)$$
(x∧(¬y))∨(y∧(¬z))
FNC
[src]
$$\left(x \vee y\right) \wedge \left(x \vee \neg z\right) \wedge \left(y \vee \neg y\right) \wedge \left(\neg y \vee \neg z\right)$$
(x∨y)∧(x∨(¬z))∧(y∨(¬y))∧((¬y)∨(¬z))