Sr Examen

Expresión P∨(Q∧R)∨(¬Q∧R)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    p∨(q∧r)∨(r∧(¬q))
    $$p \vee \left(q \wedge r\right) \vee \left(r \wedge \neg q\right)$$
    Solución detallada
    $$p \vee \left(q \wedge r\right) \vee \left(r \wedge \neg q\right) = p \vee r$$
    Simplificación [src]
    $$p \vee r$$
    p∨r
    Tabla de verdad
    +---+---+---+--------+
    | p | q | r | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$p \vee r$$
    p∨r
    FNCD [src]
    $$p \vee r$$
    p∨r
    FNDP [src]
    $$p \vee r$$
    p∨r
    FND [src]
    Ya está reducido a FND
    $$p \vee r$$
    p∨r